Equation 3
As stated before the area under the graph represents displacement
We have already shown that s = (v+u)/2 x t
Another way of representing the area under the graph is to split it into two sections;
A rectangular section with area = base x height
and a triangular section with area = 1/2 x base x height
This gives us the equation s = ut + 1/2(v-u)t
From equation 2 we know that a = (v-u)/t and therefore (v-u) = at
Therefore we can substitute the term (v-u) in the above equation for at
This gives;
s = ut + 1/2 at2 (eq. 3)
[i.e. total displacement = displacement due to initial velocity plus addition displacement due to the objects acceleration]
